Dr. Sarah's Maple Demo

**A **
**Circle and Rectangle Can Never Have Both the Same Area and Perimeter**

**A Circle and a Square Can Never Have Both the Same Area and Perimeter**

To see that a circle and a square can never have both the same area and perimeter, we simultaneously solve

these conditions for the radius of the circle, r, and the side length of the square, x. Execute the following

Maple command:

`> `
**solve({x^2=Pi*r^2,4*x=2*Pi*r},{x,r});**

** **
Notice that Maple outputs one solution.

**Why doesn't the solution give us a circle and square with equal area and perimeter. What does the solution look like geometrically?**

Now we will investigate why a circle and rectangle can never both have the same area and perimeter.

**Algebraic Explorations for Circles and Rectangles**

Let r be the radius of a circle, and x and y be the sides of a rectangle. If the area of the circle equals the area of the rectangle, then we can solve for the condition on r that this imposes:

`> `
**solve({x*y=Pi*r^2},{r});**

If the perimeter of the circle equals the perimeter of the rectangle, then we can solve for the condition on r that this imposes:

`> `
**solve({2*x+2*y=2*Pi*r},{r});**

Since the radius of a circle can never be negative, using algebra,
**we see that x+y must be equal to **

**Can you solve for x and y by hand? Explain.**

`> `
**solve(x+y=sqrt(x*y*Pi),{x,y});**

**Notice that Maple uses I to represent **

**If y is non-zero, why can't x ever be real? Explain.**

**If y is 0, then x can be real. What is x and r in this case? Why doesn't this real solution yield a circle and a rectangle with both have the same area and perimeter.**

**Graphical Explorations for Circle and Rectangle**

As above, if the perimeters and areas match up then we know that x+y equals

We'll now look at a 3d graph of the surfaces z=x+y and z=

with x values ranging from 1 to 4 and y values ranging from 1 to 4. Note that r=z, and so if we find an intersection point to the two surfaces, then that tells us that we have a solution for the radius r.

`> `
**plot3d({x+y,sqrt(x*y*Pi)}, x=1..4, y=1..4);**

**Click on the graph in Maple
and change the view to see that
there is no intersection.**